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A square plate of 10 cm side moves parallel to another plate w

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A square plate of 10 cm side moves parallel to another plate with a relative velocity of 10 cm $s^{- 1}$ , both plates immersed in water. If the viscous force is 2 x $1 0^{- 3}$ N, calculate the perpendicular distance between the plates.

0.07 cm

0.04 cm

0.06 cm

0.05 cm

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Jack Discussed

A square plate of 10 cm side moves parallel to another plate with a relative velocity of 10 cm

s^{- 1}

, both plates immersed in water. If the viscous force is 2 x

1 0^{- 3}

N, calculate the perpendicular distance between the plates.

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

side length

= 10 cm = 1 0^{- 1} m

Area of plate

= 100 \times cm^{2} = 1 0^{- 2} m^{2}

viscosity constant

= 8.9 \times 1 0^{- 4} Pa \cdot s

viscosity constant

(μ) \approx 9 \times 1 0^{- 4} Pa \cdot S

Force

(F) = 2 \times 1 0^{- 3} N

now

=

F = μ A \frac{Δ V}{Δ x} Δ V =

relative velocity

putting value

2 \times 1 0^{- 3} N = (9 \times 1 0^{- 4} Pa \cdot S) \times (1 0^{- 2} m^{2}) \times \frac{( 1 0 ^{- 1} )}{Δ x}

Δ x = 0.05 cm

Hence distance

= 0.05 cm

Correct option

(D)

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Question Text	A square plate of 10 cm side moves parallel to another plate with a relative velocity of 10 cm $s^{- 1}$ , both plates immersed in water. If the viscous force is 2 x $1 0^{- 3}$ N, calculate the perpendicular distance between the plates.
Answer Type	Text solution:1
Upvotes	150

A square plate of 10 cm side moves parallel to another plate with a relative velocity of 10 cm s−1, both plates immersed in water. If the viscous force is 2 x 10−3 N, calculate the perpendicular distance between the plates.

Text solutionVerified

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A square plate of 10 cm side moves parallel to another plate with a relative velocity of 10 cm $s^{- 1}$ , both plates immersed in water. If the viscous force is 2 x $1 0^{- 3}$ N, calculate the perpendicular distance between the plates.