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A small steel ball falls through a syrup at a constant speed of 10 m/s. If the steel ball is pulled upwards with a force equal to twice its effective weight, how fast will it move upwards?
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When the small steel falls through a syrup, only the gravitational force was acting on it.
Now, when we apply the force equal to twice the gravitational force or effective weight, then the net force magnitude becomes equal to its effective weight in the upward direction.
since the magnitude of net force remains same, so there will be no change in the velocity of the small steel. But now , it will start moving in the vertically upward direction.
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| Question Text | A small steel ball falls through a syrup at a constant speed of 10 m/s. If the steel ball is pulled upwards with a force equal to twice its effective weight, how fast will it move upwards? |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
