A ring is cut from a platinum tube having 10 cm internal and 11 cm external diameter. it is supported horizontally from a pan of the balance so that it comes in contact with water in a glass vessel. what is the surface tension of water if an extra, 4,752 gm wt is required to pull it away from water? (g = 10ms−2)

Question

A ring is cut from a platinum tube having 10 cm internal and 11 cm external diameter. it is supported horizontally from a pan of the balance so that it comes in contact with water in a glass vessel. what is the surface tension of water if an extra, 4,752 gm​ wt is required to pull it away from water? (g = 10ms−2)

Filo · Accepted Answer

Internal diameter = 10cmExternal diameter = 11cmextra mass = 4,752gmwtWe know that force due to surface tension along the Internal and external circumference of platinum tube = weight⇒Tπ(internal diameter+External diameter)=mg⇒Tπ(10+11)=4.752×1000cm/s2⇒  T=3.14×214752×103​=72.0625 dyne/cm                                     =72N/m ∴ Hence the tension is found to be 72N/m.

Question Text	A ring is cut from a platinum tube having 10 cm internal and 11 cm external diameter. it is supported horizontally from a pan of the balance so that it comes in contact with water in a glass vessel. what is the surface tension of water if an extra, $4, 752 g_{m}$ wt is required to pull it away from water? (g = $10 m s^{-} 2$ )
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