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A rigid mass less rod of length {L} is hinged at its one end a

Question

A rigid mass less rod of length $L$ is hinged at its one end a weight $W$ is hung at a distance $l (< L)$ from this end.
What is force $P$ should be applied upwards at the other end so that the rod remains in equilibrium horizontally ?
.

\frac{W ( L - l )}{L}

\frac{W ( L - l )}{l}

\frac{W l}{L}

\frac{W L}{l}

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Levi Discussed

A rigid mass less rod of length

L

is hinged at its one end a weight

W

is hung at a distance

l (< L)

from this end.
What is force

P

should be applied upwards at the other end so that the rod remains in equilibrium horizontally ?

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Question Text	A rigid mass less rod of length $L$ is hinged at its one end a weight $W$ is hung at a distance $l (< L)$ from this end. What is force $P$ should be applied upwards at the other end so that the rod remains in equilibrium horizontally ? .
Answer Type	Video solution: 1
Upvotes	151