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A proton is projected with a velocity {10}^{{{7}}}{m}{s}^{{-{1

Question

A proton is projected with a velocity $10^{7} m s^{- 1}$ , at right angles to a uniform magnetic field of induction $100 m T .$ The time $($ in second $)$ taken by the proton to traverse $90^{\circ}$ are is $: ($ Mass of proton $= 1.65 \times 10^{- 27} k g$ an charge of proton $= 1.6 \times 10^{- 19} C)$

0.81 \times 10^{- 7}

1.62 \times 10^{- 7}

2.43 \times 10^{- 7}

3.24 \times 10^{- 7}

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Sebastian Discussed

A proton is projected with a velocity

10^{7} m s^{- 1}

, at right angles to a uniform magnetic field of induction

100 m T .

The time

(

in second

)

taken by the proton to traverse

90^{\circ}

are is

: (

Mass of proton

= 1.65 \times 10^{- 27} k g

an charge of proton

= 1.6 \times 10^{- 19} C)

11 mins ago

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Question Text	A proton is projected with a velocity $10^{7} m s^{- 1}$ , at right angles to a uniform magnetic field of induction $100 m T .$ The time $($ in second $)$ taken by the proton to traverse $90^{\circ}$ are is $: ($ Mass of proton $= 1.65 \times 10^{- 27} k g$ an charge of proton $= 1.6 \times 10^{- 19} C)$
Answer Type	Video solution: 1
Upvotes	153