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A proton is bombarded on a stationary Lithium nucleus. As a re
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A proton is bombarded on a stationary Lithium nucleus. As a result of collision two α-particles are produced. The direction of motion of the α- particles with the initial direction of motion makes an anglecos−114. If B.E./Nucleon for Li7 and He4 are 5.60 MeV and 7.06 MeV respectively, then:

A
Kinetic energy of striking proton is 17.28 MeV

B
Kinetic energy of striking proton is 8.64 MeV

C
Kinetic energy of striking proton is 4.32 MeV

D
Kinetic energy of striking proton is 2.16 MeV

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A proton is bombarded on a stationary Lithium nucleus. As a result of collision two α-particles are produced. The direction of motion of the α- particles with the initial direction of motion makes an anglecos−114. If B.E./Nucleon for Li7 and He4 are 5.60 MeV and 7.06 MeV respectively, then:
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[a] Q value of the reaction Q=(2×4×7.06−7×5.6)=17.28 MeV....(i) KP+Q=2Kα                              .......(ii) 2mPKp−−−−−−√=22mαKα−−−−−−√cosα KP=Kα                                     ?...(iii) So   KP=17.28 MeV.
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Question Text
A proton is bombarded on a stationary Lithium nucleus. As a result of collision two α-particles are produced. The direction of motion of the α- particles with the initial direction of motion makes an anglecos−114. If B.E./Nucleon for Li7 and He4 are 5.60 MeV and 7.06 MeV respectively, then:
Answer TypeText solution:1
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