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Motion in Straight Line

Kinematic equations

A particle of mass 10 {~kg} starts from point A, with an initi

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A particle of mass $10 kg$ starts from point $A$ , with an initial velocity of $3 m / s$ towards negative $x$ -axis, it has been acted by a force of $10 N$ towards positive $x$ -axis. Find the distance travelled by particle in $4 s$ .

Name: Video solution 1: A particle of mass 10 kg starts from point A, with an initial velocity of 3 m/s towards negative x-axis, it has been acted by a force of 10 N towards positive x-axis. Find the distance travelled by particle in 4 s.
Uploaded: 2022-08-31T12:34:13.000Z
Duration: 4 min
Description: Video solution 1: A particle of mass 10 kg starts from point A, with an initial velocity of 3 m/s towards negative x-axis, it has been acted by a force of 10 N towards positive x-axis. Find the distance travelled by particle in 4 s.

4 m

0.5 m

4.5 m

5 m

Views: 6,059 students

Updated on: Aug 31, 2022

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2008

Found 5 tutors discussing this question

Amelia Discussed

A particle of mass

10 kg

starts from point

A

, with an initial velocity of

3 m / s

towards negative

x

-axis, it has been acted by a force of

10 N

towards positive

x

-axis. Find the distance travelled by particle in

4 s

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

This is a question based on the concept that when acceleration and initial velocity are in opposite direction, then particle comes to rest momentarily at some instant and after that direction of velocity becomes same as that of acceleration. Upto this instant, distance and displacement are equal.

a = \frac{F}{m} = \frac{10}{10} = 1 m / s^{2}

Let velocity becomes zero after

t

second, then applying

v = u + a t

\Rightarrow 0 = 3 - 1 \times t

\Rightarrow t = 3 s

\Rightarrow s_{1} = u t + \frac{1}{2} a t^{2}

= 3 \times 3 - \frac{1}{2} \times 1 \times 3^{2}

= \frac{9}{2} m = 4.5 m

[Since, the above equation is a vector equation and gives us displacement and not distance] Displacement of particle in

4 s

s = u t + \frac{1}{2} a t^{2}

= 3 \times 4 - \frac{1}{2} \times 1 \times 4^{2}

= 12 - 8 = 4 m

From the diagram, distance travelled in

4 s

= A B + BC

= 4.5 + 0.5 = 5 m

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Question Text	A particle of mass $10 kg$ starts from point $A$ , with an initial velocity of $3 m / s$ towards negative $x$ -axis, it has been acted by a force of $10 N$ towards positive $x$ -axis. Find the distance travelled by particle in $4 s$ .
Updated On	Aug 31, 2022
Topic	Motion in Straight Line
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 2
Upvotes	264
Avg. Video Duration	5 min

A particle of mass $10 kg$ starts from point $A$ , with an initial velocity of $3 m / s$ towards negative $x$ -axis, it has been acted by a force of $10 N$ towards positive $x$ -axis. Find the distance travelled by particle in $4 s$ .

Text solutionVerified

Filo tutor solutions (2)

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A particle of mass 10 kg starts from point A, with an initial velocity of 3 m/s towards negative x-axis, it has been acted by a force of 10 N towards positive x-axis. Find the distance travelled by particle in 4 s.

Text solutionVerified

Filo tutor solutions (2)

Questions from JEE Mains 2008 - PYQs

Practice questions from Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

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A particle of mass $10 kg$ starts from point $A$ , with an initial velocity of $3 m / s$ towards negative $x$ -axis, it has been acted by a force of $10 N$ towards positive $x$ -axis. Find the distance travelled by particle in $4 s$ .