A nuclear decay is expressed as ltbr. .6C11→.5B11+β++X Then the unknown particle X is

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A nuclear decay is expressed as ltbr. ._{{{6}}}{C}^{{{11}}}._{

Question

A nuclear decay is expressed as ltbr. $._{6} C^{11} \to ._{5} B^{11} + β^{+} + X$
Then the unknown particle $X$ is

neutron

antineutrino

proton

neutrino

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Charlotte Discussed

A nuclear decay is expressed as ltbr.

._{6} C^{11} \to ._{5} B^{11} + β^{+} + X

Then the unknown particle

X

12 mins ago

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Question Text

A nuclear decay is expressed as ltbr.

._{6} C^{11} \to ._{5} B^{11} + β^{+} + X

Then the unknown particle

X