Question
Medium
Solving time: 5 mins
A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4 × kg-m/s and the antineutrino 6.4 × kg-m/s. Find the recoil speed of the proton (a) if the electron and the antineutrino are ejected along the same direction and (b) if they are ejected along perpendicular directions. Mass of the proton = 1.67 × kg.
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Text solutionVerified
It is given that:
Mass of proton, mp = 1.67 × kg
Momentum of electron = 1.4 × kg m/s
Momentum of antineutrino = 6.4 × kg m/s
Let the recoil speed of the proton be Vp.
(a) When the electron and the antineutrino are ejected in the same direction,
Applying the law of conservation of momentum, we get:
(b) When the electron and the antineutrino are ejected perpendicular to each other,
Mass of proton, mp = 1.67 × kg
Momentum of electron = 1.4 × kg m/s
Momentum of antineutrino = 6.4 × kg m/s
Let the recoil speed of the proton be Vp.
(a) When the electron and the antineutrino are ejected in the same direction,
Applying the law of conservation of momentum, we get:
(b) When the electron and the antineutrino are ejected perpendicular to each other,
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Question Text | A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4 × kg-m/s and the antineutrino 6.4 × kg-m/s. Find the recoil speed of the proton (a) if the electron and the antineutrino are ejected along the same direction and (b) if they are ejected along perpendicular directions. Mass of the proton = 1.67 × kg. |
Topic | System of Particles and Rotational Motion |
Subject | Physics |
Class | Class 11 |
Answer Type | Text solution:1 |
Upvotes | 21 |