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A cubical block of side 2m and mass 20 kg slides on an incline

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A cubical block of side 2m and mass 20 kg slides on an inclined plane lubricated with the oil of viscosity $η = 1 0^{- 1}$ poise, with a constant velocity of 10 m/sec (g = 10 m/ $se c^{2}$ ). The thickness of the layer of liquid

5 mm

6 mm

4 mm

8 mm

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A cubical block of side 2m and mass 20 kg slides on an inclined plane lubricated with the oil of viscosity

η = 1 0^{- 1}

poise, with a constant velocity of 10 m/sec (g = 10 m/

se c^{2}

). The thickness of the layer of liquid

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Text solutionVerified

F = η A \frac{d v}{d z} = m g sin θ \frac{d v}{d z} = \frac{v}{h}

20 \times 10 \times sin 3 0^{\circ} = η \times 4 \times \frac{10}{h}

h = \frac{40 \times 1 0 ^{- 2}}{100} [η = 1 0^{- 1} p o i se = 1 0^{- 2} N - sec - m^{- 2}]

= 4 \times 1 0^{- 3} m = 4 mm

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Question Text	A cubical block of side 2m and mass 20 kg slides on an inclined plane lubricated with the oil of viscosity $η = 1 0^{- 1}$ poise, with a constant velocity of 10 m/sec (g = 10 m/ $se c^{2}$ ). The thickness of the layer of liquid
Answer Type	Text solution:1
Upvotes	150