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A car develops a force of 400 N and climbs up a vertical dista

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A car develops a force of 400 N and climbs up a vertical distance of 250 m. If the length of the road covered by the car is 5 km, then find the fractional change in load due to the car for the force developed.

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A car develops a force of 400 N and climbs up a vertical distance of 250 m. If the length of the road covered by the car is 5 km, then find the fractional change in load due to the car for the force developed.

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Text solutionVerified

M A = \frac{L _{c a r}}{E _{c a r}} = \frac{E A}{L A}

\frac{L _{c a r}}{400} = \frac{5000}{250}

L_{c a r} = 8000 N

Fractional change

= \frac{L _{c a r} - E}{E}

= \frac{8000 - 400}{400}

= \frac{7600}{400}

= 19

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Question Text	A car develops a force of 400 N and climbs up a vertical distance of 250 m. If the length of the road covered by the car is 5 km, then find the fractional change in load due to the car for the force developed.
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	100

A car develops a force of 400 N and climbs up a vertical distance of 250 m. If the length of the road covered by the car is 5 km, then find the fractional change in load due to the car for the force developed.

Text solutionVerified

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A car develops a force of 400 N and climbs up a vertical distance of 250 m. If the length of the road covered by the car is 5 km, then find the fractional change in load due to the car for the force developed.

Text solutionVerified

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