A block of mass m moving at speed υ collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

Question

Filo · Accepted Answer

Solution: Suppose the second block moves ast speed v towards right after the collision. From the principle of conservation of momentum.

m v = 2 m \frac{v}{or} v^{'} = \frac{v}{2}

Hence, the velocity of separation = v/2 and the velocity of approach= v. By definition ,

e = \frac{v e l o c i t y o f t h e s e p a r a t i o n}{v e l o c i t y o f a p p r o a c h} =

(v/2)/v=1/2

Question Text	A block of mass m moving at speed $υ$ collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.
Answer Type	Text solution:1
Upvotes	150

A block of mass m moving at speed υ collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

Text solutionVerified

A block of mass m moving at speed $υ$ collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.