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A ballet dancer is rotating at angular velocity on smooth hor

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A ballet dancer is rotating at angular velocity $ω$ on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by $1 / 4^{t h}$ of his initial radius of gyration, his final angular velocity is

\frac{3 ω}{4}

\frac{9 ω}{4}

\frac{9 ω}{16}

\frac{16 ω}{9}

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A ballet dancer is rotating at angular velocity

ω

on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by

1 / 4^{t h}

of his initial radius of gyration, his final angular velocity is

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Question Text	A ballet dancer is rotating at angular velocity $ω$ on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by $1 / 4^{t h}$ of his initial radius of gyration, his final angular velocity is
Answer Type	Video solution: 1
Upvotes	151