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Physics Part-II

Nuclei

A 1000 MW fission reactor consumes half of its fuel in 5.00 y.

Physics Part-II

Class 12

NCERT

Chapter 1: Ray Optics and Optical Instruments

41 questions

Chapter 2: Wave Optics

30 questions

Chapter 3: Dual Nature of Radiation and Matter

44 questions

Chapter 4: Atoms

23 questions

Chapter 5: Nuclei

38 questions

The fission properties of

_{94}^{239} P u

are very similar to those of

_{92}^{235} U

. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure

_{94}^{239} P u

undergo fission?

1000 M W

fission reactor consumes half of its fuel in

5.00 y

. How much

_{92}^{235} U

did it contain initially? Assume that the reactor operates

80%

of the time, that all the energy generated arises from the fission of

_{92}^{235} U

and that this nuclide is consumed only by the fission process.

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :

_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V

View all question

Chapter 6: Semiconductor Electronics: Materials, Devices and Simple Circuits

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Question

Medium

Solving time: 4 mins

A $1000 M W$ fission reactor consumes half of its fuel in $5.00 y$ . How much $_{92}^{235} U$ did it contain initially? Assume that the reactor operates $80%$ of the time, that all the energy generated arises from the fission of $_{92}^{235} U$ and that this nuclide is consumed only by the fission process.

Views: 5,916 students

Updated on: May 20, 2022

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Physics Part-II (NCERT)

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Liam Discussed

1000 M W

fission reactor consumes half of its fuel in

5.00 y

. How much

_{92}^{235} U

did it contain initially? Assume that the reactor operates

80%

of the time, that all the energy generated arises from the fission of

_{92}^{235} U

and that this nuclide is consumed only by the fission process.

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

The half life of the fuel is

5 ye a rs

we know that the energy produced in fission of Uranium is

200 M e V

So, energy produced by 1kg of Uranium:

E = \frac{6.022 \times 1 0 ^{23}}{235} \times 1000 \times 200

\approx 8.17 \times 1 0^{13} J

Since the reactor operate

80

of time, so time of operation is

4 ye a rs

The energy produced is:

E_{r} = 1000 \times 1066 \times 4 \times 365 \times 24 \times 60 \times 60

The mass required for producing energy is:

m = \frac{8.17 \times 1 0 ^{13} J}{1000 \times 1066 \times 4 \times 365 \times 24 \times 60 \times 60}

= 1544 k g

Since this is the amount consumed and initial amount should have been double of this. So, the initial amount of Uranium would have been

3088 k g

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Practice more questions from Physics Part-II (NCERT)

The fission properties of

_{94}^{239} P u

are very similar to those of

_{92}^{235} U

. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure

_{94}^{239} P u

undergo fission?

1000 M W

fission reactor consumes half of its fuel in

5.00 y

. How much

_{92}^{235} U

did it contain initially? Assume that the reactor operates

80%

of the time, that all the energy generated arises from the fission of

_{92}^{235} U

and that this nuclide is consumed only by the fission process.

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :

_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V

View all

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Question Text	A $1000 M W$ fission reactor consumes half of its fuel in $5.00 y$ . How much $_{92}^{235} U$ did it contain initially? Assume that the reactor operates $80%$ of the time, that all the energy generated arises from the fission of $_{92}^{235} U$ and that this nuclide is consumed only by the fission process.
Updated On	May 20, 2022
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 3
Upvotes	321
Avg. Video Duration	6 min

Text solutionVerified

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Text solutionVerified

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