Question
200 MeV of energy may be obtained per fission of U235. A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is
Found 5 tutors discussing this question
Discuss this question LIVE
15 mins ago
Text solutionVerified
[c] Power ⇒(12)4=(12)t/48⇒t=192 hour.
Was this solution helpful?
150
Share
Report
One destination to cover all your homework and assignment needs
Learn Practice Revision Succeed
Instant 1:1 help, 24x7
60, 000+ Expert tutors
Textbook solutions
Big idea maths, McGraw-Hill Education etc
Essay review
Get expert feedback on your essay
Schedule classes
High dosage tutoring from Dedicated 3 experts
Practice questions from similar books
Stuck on the question or explanation?
Connect with our physics tutors online and get step by step solution of this question.
231 students are taking LIVE classes
Question Text | 200 MeV of energy may be obtained per fission of U235. A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is |
Answer Type | Text solution:1 |
Upvotes | 150 |