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The transfer characteristic curve of a transistor, having inpu

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The transfer characteristic curve of a transistor, having input and output resistance $100Ω$ and $100 k Ω$ respectively, is shown in the figure. The voltage and power gain, are respectively.

Name: Video solution 1: The transfer characteristic curve of a transistor, having input and output resistance 100Ω and 100kΩ respectively, is shown in the figure. The voltage and power gain, are respectively.
Uploaded: 2023-01-20T12:31:19.000Z
Duration: 17 min
Description: Video solution 1: The transfer characteristic curve of a transistor, having input and output resistance 100Ω and 100kΩ respectively, is shown in the figure. The voltage and power gain, are respectively.

2.5 \times 1 0^{4}, 2.5 \times 1 0^{6}

5 \times 1 0^{4}, 5 \times 1 0^{6}

5 \times 1 0^{4}, 5 \times 1 0^{5}

5 \times 1 0^{4}, 2.5 \times 1 0^{6}

Views: 5,851 students

Updated on: Jan 20, 2023

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

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Noah Discussed

The transfer characteristic curve of a transistor, having input and output resistance

100Ω

and

100 k Ω

respectively, is shown in the figure. The voltage and power gain, are respectively.

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

Exp. (d)
Given curve is between

I_{c}

and

I_{b}

as output and input currents, respectively.
So, it is transfer characteristics curve of a common emitter (CE) configuration.
In CE configuration,
Current gain,

β = \frac{l _{o u t}}{l _{in}} = \frac{l _{c}}{l _{b}}

......(i)
Voltage gain,

A_{V} = \frac{V _{o u t}}{V _{in}} = \frac{I _{c} \times R _{o u t}}{I _{b} \times R _{in}} = β \times \frac{R _{o u t}}{R _{in}}

..........(ii)
and power gain,

A_{P} = \frac{P _{o u t}}{P _{in}} = \frac{l _{c}^{2} \times R _{o u t}}{l _{b}^{2} \times R _{in}} = β^{2} \times \frac{R _{o u t}}{R _{in}}

..............(iii)
Given,

R_{in} = 100Ω

and

R_{o u t} = 100 \times 1 0^{3} Ω

From Eq. (i), we get

β = \frac{5 mA}{100 μ A}

\frac{10 mA}{200 μ A}

\frac{15 mA}{300 μ A}

\frac{20 mA}{400 μ A}

\Rightarrow β = \frac{5 \times 1 0 ^{- 3}}{100 \times 1 0 ^{- 6}} = 50

............(iv)
From Eqs. (ii) and (iv), we get
Voltage gain,

A_{V} = β \times \frac{R _{o u t}}{R _{in}} = 50 \times \frac{100 \times 1 0 ^{3}}{100}

\Rightarrow A_{V} = 50000 = 5 \times 1 0^{4}

..........(v)
From Eqs. (iii) and (iv), we get
Power gain,

A_{P} = β^{2} \times \frac{R _{o u t}}{R _{in}} = (50)^{2} \times \frac{100 \times 1 0 ^{3}}{100}

= 2500 \times 1000

\Rightarrow A_{P} = 2.5 \times 1 0^{6}

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Question Text	The transfer characteristic curve of a transistor, having input and output resistance $100Ω$ and $100 k Ω$ respectively, is shown in the figure. The voltage and power gain, are respectively.
Updated On	Jan 20, 2023
Topic	Alternating Current
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 2
Upvotes	300
Avg. Video Duration	9 min

The transfer characteristic curve of a transistor, having input and output resistance $100Ω$ and $100 k Ω$ respectively, is shown in the figure. The voltage and power gain, are respectively.

Text solutionVerified

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The transfer characteristic curve of a transistor, having input and output resistance $100Ω$ and $100 k Ω$ respectively, is shown in the figure. The voltage and power gain, are respectively.