$y^{2} + 4 (x - a^{2}) = 0$ . One of the vertexes of $Δ^{'} (Δ)$ is a vertex of the given parabola and other two vertices are they where parabola meets they -exist. If area of $Δ$ is 250.Then a will be (A) $5$ (B) $53$ (C) $253$ (D) $35$

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y^{2} + 4 (x - a^{2}) = 0

. One of the vertexes of

Δ^{'} (Δ)

is a vertex of the given parabola and other two vertices are they where parabola meets they -exist. If area of

Δ

is 250.Then a will be (A)

5

(B)

53

(C)

253

(D)

35

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Question Text

y^{2} + 4 (x - a^{2}) = 0

. One of the vertexes of

Δ^{'} (Δ)

is a vertex of the given parabola and other two vertices are they where parabola meets they -exist. If area of

Δ

is 250.Then a will be (A)

5

(B)

53

(C)

253

(D)

35

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