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Write the first five terms of the sequence whose { n }^{ th }

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Write the first five terms of the sequence whose $n^{t h}$ term is $a_{n} = \frac{2 n - 3}{6}$

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Write the first five terms of the sequence whose

n^{t h}

term is

a_{n} = \frac{2 n - 3}{6}

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

Substituting

n = 1, 2, 3, 4, 5

, we obtain

a_{1} = \frac{2 \times 1 - 3}{6} = \frac{- 1}{6}

a_{2} = \frac{2 \times 2 - 3}{6} = \frac{1}{6}

a_{3} = \frac{2 \times 3 - 3}{6} = \frac{3}{6} = \frac{1}{2}

a_{4} = \frac{2 \times 4 - 3}{6} = \frac{5}{6}

a 5 = \frac{2 \times 5 - 3}{6} = \frac{7}{6}

Therefore the required terms are

\frac{- 1}{6}, \frac{1}{6}, \frac{1}{2}, \frac{5}{6} an d \frac{7}{6}

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Question Text	Write the first five terms of the sequence whose $n^{t h}$ term is $a_{n} = \frac{2 n - 3}{6}$
Answer Type	Text solution:1
Upvotes	150