Value of sin−1(23)+2cos−1(23) is:

sin−1(23)+2cos−1(23)=[sin−1(23)+cos−1(23)]+cos−1(23)=2π+6π=32π[∵sin−1x+cos−1x=2π]Hence, option (c) is correct.

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Value of ^{-1}({{3}}{2})+2^{-1}({{3}}{2}) is:

Question

Value of $sin^{- 1} (\frac{3}{2}) + 2 cos^{- 1} (\frac{3}{2})$ is:

\frac{π}{2}

\frac{π}{3}

\frac{2 π}{3}

π

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Scarlett Discussed

Value of

sin^{- 1} (\frac{3}{2}) + 2 cos^{- 1} (\frac{3}{2})

is:

8 mins ago

Discuss this question LIVE

8 mins ago

sin^{- 1} (\frac{3}{2}) + 2 cos^{- 1} (\frac{3}{2})

= [sin^{- 1} (\frac{3}{2}) + cos^{- 1} (\frac{3}{2})] + cos^{- 1} (\frac{3}{2})

= \frac{π}{2} + \frac{π}{6} = \frac{2 π}{3} [∵ sin^{- 1} x + cos^{- 1} x = \frac{π}{2}]

Hence, option

(c)

is correct.

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