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Using the digits of the number , how many nine digit numbers can be formed so that odd digits occupy even positions?
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There are even positions and Odd digits are in the given number.
This can be arranged in Ways
The rest digit can be arranged in Ways ( repeating times , repeating times )
Total
Hence, the answer is
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| Question Text | Using the digits of the number , how many nine digit numbers can be formed so that odd digits occupy even positions? |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
