Two lines L1:x=5,3−αy=−2z and L2:x=α,−1y=2−αz are coplanar. Then α can take value (s) a. 1 b. 2 c. 3 d. 4

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Two lines {L}_{{1}}:{x}={5},{{y}}{{{3}-}}={{z}}{{-{2}}} and {L

Question

Two lines $L_{1} : x = 5, \frac{y}{3 - α} = \frac{z}{- 2}$ and $L_{2} : x = α, \frac{y}{- 1} = \frac{z}{2 - α}$ are coplanar. Then $α$ can take value (s) a. $1$ b. $2$ c. $3$ d. $4$

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Jack Discussed

Two lines

L_{1} : x = 5, \frac{y}{3 - α} = \frac{z}{- 2}

and

L_{2} : x = α, \frac{y}{- 1} = \frac{z}{2 - α}

are coplanar. Then

α

can take value (s) a.

1

2

3

4

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Question Text

Two lines

L_{1} : x = 5, \frac{y}{3 - α} = \frac{z}{- 2}

and

L_{2} : x = α, \frac{y}{- 1} = \frac{z}{2 - α}

are coplanar. Then

α

can take value (s) a.

1

2

3

4