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Three randomly chosen nonnegative integers {x},{y}{a}{n}{.{d}{

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Three randomly chosen nonnegative integers $x, y a n d z$ are found to satisfy the equation $x + y + z = 10 .$ Then the probability that $z$ is even, is: $\frac{5}{12}$ (b) $\frac{1}{2}$ (c) $\frac{6}{11}$ (d) $\frac{36}{55}$

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Noah Discussed

Three randomly chosen nonnegative integers

x, y a n d z

are found to satisfy the equation

x + y + z = 10 .

Then the probability that

z

is even, is:

\frac{5}{12}

(b)

\frac{1}{2}

(c)

\frac{6}{11}

(d)

\frac{36}{55}

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Question Text	Three randomly chosen nonnegative integers $x, y a n d z$ are found to satisfy the equation $x + y + z = 10 .$ Then the probability that $z$ is even, is: $\frac{5}{12}$ (b) $\frac{1}{2}$ (c) $\frac{6}{11}$ (d) $\frac{36}{55}$
Answer Type	Video solution: 1
Upvotes	150