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Three boys and two girls stand in a queue. The probability, th

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Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) $\frac{1}{2}$ (B) $\frac{1}{3}$ (C) $\frac{2}{3}$ (D) $\frac{3}{4}$

Name: Video solution 1: Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) 21 (B) 31 (C) 32 (D) 43
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) 21 (B) 31 (C) 32 (D) 43

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Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A)

\frac{1}{2}

(B)

\frac{1}{3}

(C)

\frac{2}{3}

(D)

\frac{3}{4}

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Question Text	Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) $\frac{1}{2}$ (B) $\frac{1}{3}$ (C) $\frac{2}{3}$ (D) $\frac{3}{4}$
Answer Type	Video solution: 1
Upvotes	150

Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) 21​ (B) 31​ (C) 32​ (D) 43​

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Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) $\frac{1}{2}$ (B) $\frac{1}{3}$ (C) $\frac{2}{3}$ (D) $\frac{3}{4}$