Sequences and Series
There are two A.P.'s each of n terms a,a+d,a+2d,...L, p,p+q,p+2q,....L′. These A.P.'s satisfy the following conditions: pL=aL′=4,Sn′Sn=2; find out 2(L′L)
Sn′Sn=2n(p+L′) 2n(a+L) =p+4aa+4p=2 given by (1)
Putting in (2)
qd=8λ−7λ 28λ−2λ =26 and
L′L=ap=27 by (1) and (3)
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