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There are 5 white and 5 black balls marked 1, 2, ....5. In how

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There are $5$ white and $5$ black balls marked $1, 2, ....5$ . In how many ways can these balls be arranged in a row so that balls of different colours are alternate?

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There are

5

white and

5

black balls marked

1, 2, ....5

. In how many ways can these balls be arranged in a row so that balls of different colours are alternate?

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

5

white and

5

black balls are there

For the ball to be alternate in colors possibilities are

W B W B W B W B W B

B W B W B W B W B W

So a number of ways are

5! \times 5! \times 2! = 28800

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Question Text	There are $5$ white and $5$ black balls marked $1, 2, ....5$ . In how many ways can these balls be arranged in a row so that balls of different colours are alternate?
Answer Type	Text solution:1
Upvotes	150