The vertex angle of an isosceles triangle is 40∘. Find the angles of the triangle in radians(i.e., circular system).

∵ ∠A=40∘ i.e., ∠A=40×180πc \left [ 1^{\circ} = \dfrac{\pi^{c}}{180} \right ] ⇒ ∠A=92πc ∵ AB=AC (given) ∴ Other base angles must be of 70∘ each.∴ ∠B=70∘=70×180πc ⇒ ∠B=187πc ∴ ∠C=187πc

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The vertex angle of an isosceles triangle is 40^{} . Find the

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The vertex angle of an isosceles triangle is $4 0^{\circ}$ . Find the angles of the triangle in radians(i.e., circular system).

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The vertex angle of an isosceles triangle is

4 0^{\circ}

. Find the angles of the triangle in radians(i.e., circular system).

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Text solutionVerified

∵

∠ A = 4 0^{\circ}

i.e.,

∠ A = 40 \times \frac{π ^{c}}{180}

\left [ 1^{\circ} = \dfrac{\pi^{c}}{180} \right ]

\Rightarrow

∠ A = \frac{2 π ^{c}}{9}

∵

A B = A C

(given)

∴

Other base angles must be of

7 0^{\circ}

each.

∴

∠ B = 7 0^{\circ} = 70 \times \frac{π ^{c}}{180}

\Rightarrow

∠ B = \frac{7 π ^{c}}{18}

∴

∠ C = \frac{7 π ^{c}}{18}

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Question Text	The vertex angle of an isosceles triangle is $4 0^{\circ}$ . Find the angles of the triangle in radians(i.e., circular system).
Answer Type	Text solution:1
Upvotes	150

The vertex angle of an isosceles triangle is 40∘. Find the angles of the triangle in radians(i.e., circular system).

Text solutionVerified

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The vertex angle of an isosceles triangle is $4 0^{\circ}$ . Find the angles of the triangle in radians(i.e., circular system).