The value of tan−1[1+x2−1−x21+x2+1−x2],∣x∣<21,x=0, is equal to:

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The value of ^{-1}[{{1+x^{2}}+{1-x^{2}}}{{1+x^{2}}-{1-x^{2}}}]

Question

The value of $tan^{- 1} [\frac{1 + x ^{2} + 1 - x ^{2}}{1 + x ^{2} - 1 - x ^{2}}], ∣ x ∣ < \frac{1}{2}, x = 0$ , is equal to:

\frac{p i}{4} - cos^{- 1} x^{2}

\frac{p i}{4} + \frac{1}{2} cos^{- 1} x^{2}

\frac{p i}{4} + cos^{- 1} x^{2}

\frac{p i}{4} - \frac{1}{2} cos^{- 1} x^{2}

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The value of

tan^{- 1} [\frac{1 + x ^{2} + 1 - x ^{2}}{1 + x ^{2} - 1 - x ^{2}}], ∣ x ∣ < \frac{1}{2}, x = 0

, is equal to:

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Question Text

The value of

tan^{- 1} [\frac{1 + x ^{2} + 1 - x ^{2}}{1 + x ^{2} - 1 - x ^{2}}], ∣ x ∣ < \frac{1}{2}, x = 0

, is equal to: