The value of k=0∑7⎣⎡(14k)(7k)r=k∑14(rk)(14r)⎦⎤, where (nr) denotes nCr is
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If the middle term in the expansion of (x2+1/x)n
then find the value of n˙
Find the sum of 1!(n−1)!1+3!(n−3)1+5!(n−5)1+,
Find the sum 1−81+81×163−8×16×241×3×5+
Using the binomial theorem, evaluate (102)5
Expand of the expression : (1−2x)5
If the coefficients of (r−5)th and (2r−1)thterms of the expansion (1+x)34 are equal, find r.
is very large as compare to y,
prove that x+yxx−yx˙=1+2x2y2
If 97+79 is divisible b 2n, then find the greatest value of n,wheren∈N˙