The value of 3cosec20∘−sec20∘ is equal to

a=3csc20−sec20 ⇒a=sin20cos20 3cos20−sin20 =2sin20cos20 4(sin60cos20−cos60sin20 ) ⇒a=sin40 4sin40 =4{∵2sinAcosA=sin2A&sinAcosB−cosAsinB=sin(A−B) } Ans: B

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The value of {3}co 20^{}- 20^{} is equal to

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The value of $3 co sec 2 0^{\circ} - sec 2 0^{\circ}$ is equal to

2 \cdot \frac{sin 2 0 ^{\circ}}{sin 4 0 ^{\circ}}

4 \cdot \frac{sin 2 0 ^{\circ}}{sin 4 0 ^{\circ}}

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3 co sec 2 0^{\circ} - sec 2 0^{\circ}

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Text solutionVerified

a = 3 csc 20 - sec 20

\Rightarrow a = \frac{3 cos 20 - sin 20}{sin 20 cos 20} = \frac{4 ( sin 60 cos 20 - cos 60 sin 20 )}{2 sin 20 cos 20}

\Rightarrow a = \frac{4 sin 40}{sin 40} = 4 {∵ 2 sin A cos A = sin 2 A & sin A cos B - cos A sin B = sin (A - B)}

Ans: B

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Question Text	The value of $3 co sec 2 0^{\circ} - sec 2 0^{\circ}$ is equal to
Answer Type	Text solution:1
Upvotes	150

The value of 3​cosec20∘−sec20∘ is equal to

Text solutionVerified

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The value of $3 co sec 2 0^{\circ} - sec 2 0^{\circ}$ is equal to