The value of r=1∑na+rx+a+(r−1)x 1 is

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The value of _{ r=1 }^{ n }{ { 1 }{ { a+rx } + { a+( r-1 )

Question

The value of $r = 1 \sum n \frac{1}{a + r x + a + ( r - 1 ) x}$ is

\frac{n}{a + a + n x}

\frac{n}{a - a + n x}

\frac{a + n x - a}{x}

\frac{a + a + n x}{x}

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The value of

r = 1 \sum n \frac{1}{a + r x + a + ( r - 1 ) x}

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Question Text

The value of

r = 1 \sum n \frac{1}{a + r x + a + ( r - 1 ) x}