The value of $co s^{2} 3 0^{0} - co s^{2} 6 0^{0} - cos 6 0^{0}$ is

0

\frac{1}{2}

\frac{3}{4}

1

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co s^{2} 3 0^{0} - co s^{2} 6 0^{0} - cos 6 0^{0}

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Text solutionVerified

co s^{2} 3 0^{0} - co s^{2} 6 0^{0} - cos 6 0^{0} = (\frac{3}{2})^{2} - (\frac{1}{2})^{2} - \frac{1}{2} = \frac{3}{4} - \frac{1}{4} - \frac{1}{2} = \frac{3 - 1 - 2}{4} = 0

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