The total number of words that can be made by writing the letters of the word PARAMETER so that no vowel is between two consonants is 

Given,
PARAMETER
no vowel is between two consonants i.e. all the consonants are together
let all the consonants be treated as one letter
hence now there are $5$ letters which can be arranged in $5!$ ways as $A$ and $E$ are repeated so we divide it by $2!2!$
Now $5$ consonants can be arranged in $5!$ ways as $R$ is repeating twice we should divide it by $2!$
$\therefore$ the number of ways are $\frac{5!5!}{2!2!2!}$=1800
Hence option B is correct