The total number of ways of selecting two numbers from the set {1,2,3,4,……..3n} so that their sum is divisible by 3 is equal to a. 22n2−n b. 23n2−n c. 2n2−n d. 3n2−n

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The total number of ways of selecting two numbers from the set

Question

The total number of ways of selecting two numbers from the set ${1, 2, 3, 4, \dots\dots . .3 n}$ so that their sum is divisible by 3 is equal to a. $\frac{2 n ^{2} - n}{2}$ b. $\frac{3 n ^{2} - n}{2}$ c. $2 n^{2} - n$ d. $3 n^{2} - n$

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The total number of ways of selecting two numbers from the set

{1, 2, 3, 4, \dots\dots . .3 n}

so that their sum is divisible by 3 is equal to a.

\frac{2 n ^{2} - n}{2}

\frac{3 n ^{2} - n}{2}

2 n^{2} - n

3 n^{2} - n

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Question Text

The total number of ways of selecting two numbers from the set

{1, 2, 3, 4, \dots\dots . .3 n}

so that their sum is divisible by 3 is equal to a.

\frac{2 n ^{2} - n}{2}

\frac{3 n ^{2} - n}{2}

2 n^{2} - n

3 n^{2} - n