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The straight line {{{x}}}{{{4}}}+{{{y}}}{{{3}}}={1} intersects

Question

The straight line $\frac{x}{4} + \frac{y}{3} = 1$ intersects the ellipse $\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1$ at two points A and B, there is a point P on this ellipse such that the area of $Δ P A B$ is equal to $6 (2 - 1)$ . Then the number of such points (P) is/are

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Scarlett Discussed

The straight line

\frac{x}{4} + \frac{y}{3} = 1

intersects the ellipse

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

at two points A and B, there is a point P on this ellipse such that the area of

Δ P A B

is equal to

6 (2 - 1)

. Then the number of such points (P) is/are

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Question Text

The straight line

\frac{x}{4} + \frac{y}{3} = 1

intersects the ellipse

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

at two points A and B, there is a point P on this ellipse such that the area of

Δ P A B

is equal to

6 (2 - 1)

. Then the number of such points (P) is/are

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