The straight line 2x-3y = 1 divides the circular region x2+y2≤6 into two parts. If S = { (2,43),(25,43),(41,−41),(81,41)}, then the number of point(s) in S lying inside the smaller part is

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The straight line 2x-3y = 1 divides the circular region {x}^{{

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The straight line 2x-3y = 1 divides the circular region $x^{2} + y^{2} \leq 6$ into two parts. If S = { $(2, \frac{3}{4}), (\frac{5}{2}, \frac{3}{4}), (\frac{1}{4}, - \frac{1}{4}), (\frac{1}{8}, \frac{1}{4})$ }, then the number of point(s) in S lying inside the smaller part is

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James Discussed

The straight line 2x-3y = 1 divides the circular region

x^{2} + y^{2} \leq 6

into two parts. If S = {

(2, \frac{3}{4}), (\frac{5}{2}, \frac{3}{4}), (\frac{1}{4}, - \frac{1}{4}), (\frac{1}{8}, \frac{1}{4})

}, then the number of point(s) in S lying inside the smaller part is

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Question Text	The straight line 2x-3y = 1 divides the circular region $x^{2} + y^{2} \leq 6$ into two parts. If S = { $(2, \frac{3}{4}), (\frac{5}{2}, \frac{3}{4}), (\frac{1}{4}, - \frac{1}{4}), (\frac{1}{8}, \frac{1}{4})$ }, then the number of point(s) in S lying inside the smaller part is
Answer Type	Video solution: 1
Upvotes	150