The solution of the equation sin−1(dxdt)=x+y is

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The solution of the equation sin^{-1}({dt}{dx})=x+y is

Question

The solution of the equation $s i n^{- 1} (\frac{d t}{d x}) = x + y$ is

tan(x+y)+sec(x+y)=x+c

tan(x+y)-sec(x+y)=x+c

tan(x+y)+sec(x+y)+x+c=0

None of these

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s i n^{- 1} (\frac{d t}{d x}) = x + y

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Question Text

The solution of the equation

s i n^{- 1} (\frac{d t}{d x}) = x + y