The solution of the equation dxdy=siny+ycosyx(2logx+1) is

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The solution of the equation {{{.{d}{y}.}}}{{{.{d}{x}.}}}={{{x

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The solution of the equation $\frac{d y}{d x} = \frac{x ( 2 lo g x + 1 )}{sin y + y cos y}$ is

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The solution of the equation

\frac{d y}{d x} = \frac{x ( 2 lo g x + 1 )}{sin y + y cos y}

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Question Text

The solution of the equation

\frac{d y}{d x} = \frac{x ( 2 lo g x + 1 )}{sin y + y cos y}