The remainder left out when 82n(62)2n+1is divided by 9 is
Connecting you to a tutor in 60 seconds.
Get answers to your doubts.
Find the middle terms in the expansion of (3−6x3 )7
Find the coefficient of x5 in the product (1+2x)6(1−x)7 using binomial theorem.
Middle term in expansion of (1−3x+3x2−x3)2n is
74C37−2 is divisibl by
The sum of the coefficients of first three term in the expansion of (x−x23)m,x=0.
m being a natural number, is 559. Find the term of the expansion containing x3.
Evaluate the following: (3+2)6−(3−2)6
Find the 7th term in the expansion of (3x2−x31)10˙
Find the coefficient of x5 in (x+3)8