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The product of five consecutive numbers is always divisible by

Question

The product of five consecutive numbers is always divisible by ?

A

60

B

12

C

120

D

72

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Text solutionVerified

Solution:

The product

(n)

of any

5

consecutive numbers will always be divisible by

120

and its factors.

n (n + 1) (n + 2) (n + 3) (n + 4)

5 \times 4 \times 3 \times 2 = 120

Answer C:

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Question Text	The product of five consecutive numbers is always divisible by ?
Answer Type	Text solution:1
Upvotes	156