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The point (x_{1}, y_{1}), (x_{2}, y_{2}), (x_{1}, y_{2}) & (x_

Question

The point $(x_{1}, y_{1}), (x_{2}, y_{2}), (x_{1}, y_{2})$ & $(x_{2}, y_{1})$ are always

Collinear

Concyclic

Vertices of a square

Vertices of a rhombus.

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The point

(x_{1}, y_{1}), (x_{2}, y_{2}), (x_{1}, y_{2})

(x_{2}, y_{1})

are always

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

Let the coordinates be denoted as

A (x_{1}, y_{2})

B (x_{2}, y_{2})

C (x_{2}, y_{1})

and

D (x_{1}, y_{1})

Plot the given points on a graph as above,

It is not necessary that

∣ x_{2} - x_{1} ∣ = ∣ y_{2} - y_{1} ∣

With

(x_{2}, y_{1})

and

(x_{1}, y_{2})

as ends of diameter

∠ A BC = 9 0^{\circ}

and

∠ A D C = 9 0^{\circ}

∴ A BC D

are concyclic.

So,

B

is the correct option.

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Question Text	The point $(x_{1}, y_{1}), (x_{2}, y_{2}), (x_{1}, y_{2})$ & $(x_{2}, y_{1})$ are always
Answer Type	Text solution:1
Upvotes	150

The point (x1​,y1​),(x2​,y2​),(x1​,y2​) & (x2​,y1​) are always

Text solutionVerified

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The point $(x_{1}, y_{1}), (x_{2}, y_{2}), (x_{1}, y_{2})$ & $(x_{2}, y_{1})$ are always