The point of intersection of the lines 3x−5=−1y−7=1z+2 and −36x+3=2y−3=4z−6 is (A) (21,35,310) (B) (2,10,4) (C) (−3,3,6) (D) (5,7,−2)

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The point of intersection of the lines {{{x}-{5}}}{{3}}={{{y}-

Question

The point of intersection of the lines $\frac{x - 5}{3} = \frac{y - 7}{- 1} = \frac{z + 2}{1}$ and $\frac{x + 3}{- 36} = \frac{y - 3}{2} = \frac{z - 6}{4}$ is (A) $(21, \frac{5}{3}, \frac{10}{3})$ (B) $(2, 10, 4)$ (C) $(- 3, 3, 6)$ (D) $(5, 7, - 2)$

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The point of intersection of the lines

\frac{x - 5}{3} = \frac{y - 7}{- 1} = \frac{z + 2}{1}

and

\frac{x + 3}{- 36} = \frac{y - 3}{2} = \frac{z - 6}{4}

is (A)

(21, \frac{5}{3}, \frac{10}{3})

(B)

(2, 10, 4)

(C)

(- 3, 3, 6)

(D)

(5, 7, - 2)

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Question Text

The point of intersection of the lines

\frac{x - 5}{3} = \frac{y - 7}{- 1} = \frac{z + 2}{1}

and

\frac{x + 3}{- 36} = \frac{y - 3}{2} = \frac{z - 6}{4}

is (A)

(21, \frac{5}{3}, \frac{10}{3})

(B)

(2, 10, 4)

(C)

(- 3, 3, 6)

(D)

(5, 7, - 2)