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The point of intersection of the line passing through {({0},{0

Question

The point of intersection of the line passing through $(0, 0, 1)$ and intersecting the lines $x + 2 y + z = 1, - x + y - 2 z = 2$ and $x + y = 2, x + z = 2$ with $x y$ plane is a. $(\frac{5}{3}, - \frac{1}{3}, 0)$ b. $(1, 1, 0)$ c. $(\frac{2}{3}, \frac{1}{3}, 0)$ d. $(- \frac{5}{3}, \frac{1}{3}, 0)$

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Harper Discussed

The point of intersection of the line passing through

(0, 0, 1)

and intersecting the lines

x + 2 y + z = 1, - x + y - 2 z = 2

and

x + y = 2, x + z = 2

with

x y

plane is a.

(\frac{5}{3}, - \frac{1}{3}, 0)

(1, 1, 0)

(\frac{2}{3}, \frac{1}{3}, 0)

(- \frac{5}{3}, \frac{1}{3}, 0)

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Question Text

The point of intersection of the line passing through

(0, 0, 1)

and intersecting the lines

x + 2 y + z = 1, - x + y - 2 z = 2

and

x + y = 2, x + z = 2

with

x y

plane is a.

(\frac{5}{3}, - \frac{1}{3}, 0)

(1, 1, 0)

(\frac{2}{3}, \frac{1}{3}, 0)

(- \frac{5}{3}, \frac{1}{3}, 0)

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