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The point diametrically opposite to the point P (1, 0) on the

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The point diametrically opposite to the point P (1, 0) on the circle $x^{2} + y^{2} + 2 x + 4 y - 3 = 0$ is

(3, - 4)

(- 3, 4)

(- 3, - 4)

(3, 4)

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Liam Discussed

The point diametrically opposite to the point P (1, 0) on the circle

x^{2} + y^{2} + 2 x + 4 y - 3 = 0

5 mins ago

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Question Text	The point diametrically opposite to the point P (1, 0) on the circle $x^{2} + y^{2} + 2 x + 4 y - 3 = 0$ is
Answer Type	Video solution: 1
Upvotes	150