The numerically greatest term in the expansion of (3−2x)9 when x=1 is
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Expand using Binomial Theorem (1+2x−x2)4,x=0 and let the sum of coefficients of the terms in the expansion be t. Find 10000t
If 4−x(1−3x)1/2+(1−x)5/3 is approximately equal to a+bx for small values of x, then (a,b)=
The remainder when 2710+751 is divided by 10
Let t100=r=0∑100(100Cr)51 and S100=r=0∑100(100Cr)5r, then the value of S100100t100 is
The expansion 1+x,1+x+x2,1+x+x2+x3,….1+x+x2+…+x20 are multipled together and the terms of the product thus obtained are arranged in increasing powers of x in the form of a0+a1x+a2x2+…, then, Sum of coefficients of even powers of x is
The term independent of x in the product (4+x+7x2)(x−x3)11 is
Find the 7th term in the expansion of (3x2−x31)10˙
Find the coefficient of x5
in the expansioin of the product (1+2x)6(1−x)7˙