The number of ways in which 5 boys and 5 girls can be seated for a photograph, so that no two girls sit next to each other is :

Boys will arrange themselves in $5!$ Ways   _B1_B2_B3_B4_B5_ 

And places left will be occupied by girls in  ${}^6{\text{P}}_5$ Ways

$5!\times {}^6{\text{P}}_5=5!\times 6!$

$5!\times {}^6{\text{P}}_5=720$

The answer will be option A