The number of such numbers which are divisible by two and five (all digits are not different) is

The numbers which are divisible by 2 and 5 are the multiples of 10.
Hence the ending digit has to be 0.
However the starting digit cannot be 0.
Now 
_ _ _ 0.
Hence number of ways of filling the first place will be 4, the second place will be 5 and 3rd place will be 5, since repetition of digits are allowed.
Hence total number of the numbers which are divisible by 2 and 5 are 
$4\times 5\times 5$
$=100$