Class 11

Math

Co-ordinate Geometry

Straight Lines

The number of such numbers which are divisible by two and five (all digits are not different) is

- 125
- 76
- 65
- 100

Hence the ending digit has to be 0.

However the starting digit cannot be 0.

Now

_ _ _ 0.

Hence number of ways of filling the first place will be 4, the second place will be 5 and 3rd place will be 5, since repetition of digits are allowed.

Hence total number of the numbers which are divisible by 2 and 5 are

$4×5×5$

$=100$