The number of five-digit numbers that contain 7 exactly once is a. $(41) (9^{3})$ b. $(37) (9^{3})$ c. $(7) (9^{4})$ d. $(41) (9^{4})$

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The number of five-digit numbers that contain 7 exactly once is a.

(41) (9^{3})

(37) (9^{3})

(7) (9^{4})

(41) (9^{4})

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Question Text

The number of five-digit numbers that contain 7 exactly once is a.

(41) (9^{3})

(37) (9^{3})

(7) (9^{4})

(41) (9^{4})

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