The nth terms of an A.P m1,mm+1,m2m+1 is

a=m1d=mm+1−m1=1m1−m1=1∴tn=+(n−1)d=m1+(n−1)=mmn−m+1

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The n^{th} terms of an A.P {1}{m},{m+1}{m},{2m+1}{m} is

Question

The $n^{t h}$ terms of an A.P $\frac{1}{m}, \frac{m + 1}{m}, \frac{2 m + 1}{m}$ is

\frac{m + 1 - mn}{m}

\frac{mn - m + 1}{m}

\frac{mn - m - n}{m}

\frac{mn + m - n}{m}

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Noah Discussed

The

n^{t h}

terms of an A.P

\frac{1}{m}, \frac{m + 1}{m}, \frac{2 m + 1}{m}

10 mins ago

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10 mins ago

a = \frac{1}{m}

d = \frac{m + 1}{m} - \frac{1}{m} = 1 \frac{1}{m} - \frac{1}{m} = 1

∴ t_{n} = + (n - 1) d = \frac{1}{m} + (n - 1) = \frac{mn - m + 1}{m}

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Question Text	The $n^{t h}$ terms of an A.P $\frac{1}{m}, \frac{m + 1}{m}, \frac{2 m + 1}{m}$ is
Answer Type	Text solution:1
Upvotes	150