The lengths of the sides of an isosceles triangle are $9 + x^{2}, 9 + x^{2}$ and $18 - 2 x^{2}$ units. Calculate the area of the triangle in terms of x and find the value of x which makes the area maximum.

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The lengths of the sides of an isosceles triangle are

9 + x^{2}, 9 + x^{2}

and

18 - 2 x^{2}

units. Calculate the area of the triangle in terms of x and find the value of x which makes the area maximum.

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Question Text

The lengths of the sides of an isosceles triangle are

9 + x^{2}, 9 + x^{2}

and

18 - 2 x^{2}

units. Calculate the area of the triangle in terms of x and find the value of x which makes the area maximum.

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