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The largest interval lying in {(-{}{{2}},{}{{2}})}for which th

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The largest interval lying in $(- \frac{π}{2}, \frac{π}{2})$ for which the function \displaystyle{\left[{f{{\left({x}\right)}}}={4}^{{-{{x}}}}^{2}+{{\cos}^{{-{1}}}{\left(\frac{{x}}{{2}}-{1}\right)}}+{\log{{\left({\cos{{x}}}\right)}}}\right]} is defined, is

[0, π]

(- \frac{π}{2}, \frac{π}{2})

[- \frac{π}{4}, \frac{π}{2})

[0, \frac{π}{2})

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The largest interval lying in

(- \frac{π}{2}, \frac{π}{2})

for which the function \displaystyle{\left[{f{{\left({x}\right)}}}={4}^{{-{{x}}}}^{2}+{{\cos}^{{-{1}}}{\left(\frac{{x}}{{2}}-{1}\right)}}+{\log{{\left({\cos{{x}}}\right)}}}\right]} is defined, is

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Question Text	The largest interval lying in $(- \frac{π}{2}, \frac{π}{2})$ for which the function \displaystyle{\left[{f{{\left({x}\right)}}}={4}^{{-{{x}}}}^{2}+{{\cos}^{{-{1}}}{\left(\frac{{x}}{{2}}-{1}\right)}}+{\log{{\left({\cos{{x}}}\right)}}}\right]} is defined, is
Answer Type	Video solution: 1
Upvotes	150

The largest interval lying in (−2π​,2π​)for which the function \displaystyle{\left[{f{{\left({x}\right)}}}={4}^{{-{{x}}}}^{2}+{{\cos}^{{-{1}}}{\left(\frac{{x}}{{2}}-{1}\right)}}+{\log{{\left({\cos{{x}}}\right)}}}\right]} is defined, is

Filo tutor solutions (1)

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The largest interval lying in $(- \frac{π}{2}, \frac{π}{2})$ for which the function \displaystyle{\left[{f{{\left({x}\right)}}}={4}^{{-{{x}}}}^{2}+{{\cos}^{{-{1}}}{\left(\frac{{x}}{{2}}-{1}\right)}}+{\log{{\left({\cos{{x}}}\right)}}}\right]} is defined, is